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未验证 提交 f3559f52 编辑于 作者: dlagul's avatar dlagul 提交者: GitHub
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Update tester.py

上级 d22a3a25
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...@@ -84,7 +84,7 @@ class Tester(object): ...@@ -84,7 +84,7 @@ class Tester(object):
# See https://arxiv.org/pdf/1606.05908.pdf, Page 9, Section 2.2 for details. # See https://arxiv.org/pdf/1606.05908.pdf, Page 9, Section 2.2 for details.
# The constant items in the loss function (not the coefficients) can be any number here, or even omitted # The constant items in the loss function (not the coefficients) can be any number here, or even omitted
# due to they have no any impact on gradientis propagation during training. So do in testing. # due to they have no any impact on gradientis propagation during training. So do in testing.
# log(N(x|mu,sigma^2)) # log(N(x|mean,var)) = log(N(x|mu,sigma^2))
# = log{1/(sqrt(2*pi)*sigma)exp{-(x-mu)^2/(2*sigma^2)}} # = log{1/(sqrt(2*pi)*sigma)exp{-(x-mu)^2/(2*sigma^2)}}
# = -0.5*{log(2*pi)+2*log(sigma)+[(x-mu)/exp{log(sigma)}]^2} # = -0.5*{log(2*pi)+2*log(sigma)+[(x-mu)/exp{log(sigma)}]^2}
# Note that var = sigma^2, i.e., log(var) = 2*log(sigma) # Note that var = sigma^2, i.e., log(var) = 2*log(sigma)
...@@ -107,7 +107,7 @@ class Tester(object): ...@@ -107,7 +107,7 @@ class Tester(object):
# The constant items in the loss function (not the coefficients) can be any number here, or even omitted # The constant items in the loss function (not the coefficients) can be any number here, or even omitted
# due to they have no any impact on gradientis propagation during training. # due to they have no any impact on gradientis propagation during training.
# So do in testing, because they also have no any impact on the results (all anomaly scores increase or decrease to the same extent). # So do in testing, because they also have no any impact on the results (all anomaly scores increase or decrease to the same extent).
# log(N(x|mu,sigma^2)) # log(N(x|mean,var)) = log(N(x|mu,sigma^2))
# = log{1/(sqrt(2*pi)*sigma)exp{-(x-mu)^2/(2*sigma^2)}} # = log{1/(sqrt(2*pi)*sigma)exp{-(x-mu)^2/(2*sigma^2)}}
# = -0.5*{log(2*pi)+2*log(sigma)+[(x-mu)/exp{log(sigma)}]^2} # = -0.5*{log(2*pi)+2*log(sigma)+[(x-mu)/exp{log(sigma)}]^2}
# Note that var = sigma^2, i.e., log(var) = 2*log(sigma) # Note that var = sigma^2, i.e., log(var) = 2*log(sigma)
......
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